550x+10-4.9x^2=0

Solution for 550x+10-4.9x^2=0 equation:

550x+10-4.9x^2=0

a = -4.9; b = 550; c = +10;
Δ = b2-4ac
Δ = 5502-4·(-4.9)·10
Δ = 302696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{302696}=\sqrt{4*75674}=\sqrt{4}*\sqrt{75674}=2\sqrt{75674}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(550)-2\sqrt{75674}}{2*-4.9}=\frac{-550-2\sqrt{75674}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(550)+2\sqrt{75674}}{2*-4.9}=\frac{-550+2\sqrt{75674}}{-9.8}
$